Fun Programming Problem

[abir]

take the following code:

int i, n = 20; 
for (i=0; i<n; i--) 
{ 
cout << "x" << endl; 
}

by changing only ONE character in the above code, meaning you cannot change 20 to 31, because you will have changed two characters, you can change 20 to 21, because you only changed the 0, do the following:

find 3 ways to make the above code print x 20 times (by changing only one character).

If you find all the THREE ways, post in spoiler.
Don't post result without SPOILER.

[Taher furious]

take the following code:

int i, n = 20; 
for (i=0; i<n; i--) 
{ 
cout << "x" << endl; 
}

by changing only ONE character in the above code, meaning you cannot change 20 to 31, because you will have changed two characters, you can change 20 to 21, because you only changed the 0, do the following:

find 3 ways to make the above code print x 20 times (by changing only one character).

If you find all the THREE ways, post in spoiler.
Don't post result without SPOILER.

what????
:O @abir bhai shoytan i-- disen issa kore emnitei unlimited astese

[CvP]

solution #1:

int i, n = 20; 
for (i=0; i<n; n--) 
{ 
cout << "x" << endl; 
}

solution #2:

int i, n = 20; 
for (i=0; i+n; i--) 
{ 
cout << "x" << endl; 
}

solution #3:

int i, n = 20; 
for (i=0;-i<n; i--) 
{ 
cout << "x" << endl; 
}

[abir]

solution #1:

int i, n = 20; 
for (i=0; i<n; n--) 
{ 
cout << "x" << endl; 
}

solution #2:

int i, n = 20; 
for (i=0; i+n; i--) 
{ 
cout << "x" << endl; 
}

There is another one, i found that first but missed your #2! you can consider whitespace as a character

what????
:O @abir bhai shoytan i-- disen issa kore emnitei unlimited astese

Yah your duty is make it print 20 times just changing a character in 3 ways

[Taher furious]

Yah your duty is make it print 20 times just changing a character in 3 ways

ami parsi 1bar tao 2ta character change kore...++ ke -- the easiest way [SPOILER]

int i, n = 20;  for (i=0; i<n; i++)  {  cout << "x" << endl;  }

[/SPOILER]

---------- Post added at 19:19 ---------- Previous post was at 19:17 ----------

solution #2:

int i, n = 20; 
for (i=0; i+n; i--) 
{ 
cout << "x" << endl; 
}

porer code ta bujlam na

[abir]

@Taher fu®ious™
Two character replacing is not allowed.

Also edit your post please, you are supposed to post answer within spoiler. Hide the CvP's one with spoiler tag.

---------- Post added at 19:50 ---------- Previous post was at 19:32 ----------

@Taher fu®ious™

Here is the explanation of that code:

explanation:

for( ; ; )
In the for loop, semi colon (; ) separated fields are -
The 1st field is for initialization.
The 2nd field is for condition.
The 3rd field is for action per loop.

So the `i+n` is the condition. when the condition is not false or not 0, the loop continues.
In the 20th iteration the `i+n` becomes `-20+20`= 0 and the loop breaks.

[Taher furious]

:O thnx a lot!! 10ta repu paona!

[areek]

So, addition n deletion aren't allowed???

---------- Post added at 20:17 ---------- Previous post was at 20:12 ----------

wrong ans:

int i, n = -20;
for (i=0; i<n; i--)
{
cout << "x" << endl;
}

---------- Post added at 20:18 ---------- Previous post was at 20:17 ----------

I think this is the ans u r lookin for @abir vai, what is left of CvP bro???
Not sure abt it tho, i didnt put it in a compiler, just thought.

[abir]

So, addition n deletion aren't allowed???
---------- Post added at 20:17 ---------- Previous post was at 20:12 ----------

ans:

int i, n = -20;
for (i=0; i<n; i--)
{
cout << "x" << endl;
}

---------- Post added at 20:18 ---------- Previous post was at 20:17 ----------
I think this is the ans u r lookin for @abir vai, what is left of CvP bro???
Not sure abt it tho, i didnt put it in a compiler, just thought.

To be precise, you can replace a whitespace character, that means you can add.

Your answer is not correct. n =-20 it doesn't satisfy the condition i<n (0<-20) so the inside for loop won't be executed no x will be printed.

CvP added the 3rd solution already

[areek]

To be precise, you can replace a whitespace character, that means you can add.

Your answer is not correct. n =-20 it doesn't satisfy the condition i<n (0<-20) so the inside for loop won't be executed no x will be printed.

CvP added the 3rd solution already

hmm....it was a blind guess

[pollob.codename13]

2 ta solution bair korte parsi

1:

int i, n = 20; 
for (i=0; i<n; n--) 
{ 
cout << "x" << endl; 
}

2:

int i, n = 20; 
for (i=0;-i<n; i--) 
{ 
cout << "x" << endl; 
}

[akk]

panic of 1/1